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Equilibrium involving chemical processes: Law of chemical equilibrium, equilibrium constants (Kp and Kc) and their significance, the significance of Delta G and Delta G° in chemical equilibrium MCQs for JEE

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Master Equilibrium involving chemical processes: Law of chemical equilibrium, equilibrium constants (Kp and Kc) and their significance, the significance of Delta G and Delta G° in chemical equilibrium through exam-style multiple-choice questions. This page features 27+ JEE MCQs covering Equilibrium involving chemical processes: Law of chemical equilibrium, equilibrium constants (Kp and Kc) and their significance, the significance of Delta G and Delta G° in chemical equilibrium, each with verified answers and clear explanations.

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Part of Equilibrium in JEE Main Chemistry.

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Q1ChemistryUnit 6: Equilibrium

One mole of ethanol is treated with one mole of ethanoic acid at

25 .

One-forth of the acid changes into ester at equilibrium. The equilibrium constant for the reaction will be:

Q2ChemistryUnit 6: Equilibrium

2 moles of

P C l_{5}

when heated in a closed vessels of 2 litre capacity at equilibrium

40 \%

P C l_{5}

dissociated in

P C l_{3}

and

C l_{2} .

What is the value of the equilibrium constant?

Q3ChemistryUnit 6: Equilibrium

56 \mathrm{g}

of nitrogen and

8 \mathrm{g}

of hydrogen gas are heated in a closed vessel. At equilibrium, 34 g of ammonia are present. The equilibrium number of moles of nitrogen, hydrogen and ammonia are respectively:

Q4ChemistryUnit 6: Equilibrium

A+B \rightleftharpoons C+D, K_{c}

for this reaction is 10. If 1,2,3,4 mole/litre of

A, B, C

and

D

respectively are present in a container at

25^{\circ} C,

the direction of reaction will be:

Q5ChemistryUnit 6: Equilibrium

For the system

\boldsymbol{A}_{(g)}+\mathbf{2} \boldsymbol{B}_{(\boldsymbol{g})} \rightleftharpoons \boldsymbol{C}_{(g)},

the equilibrium concentrations are

\boldsymbol{A}=\mathbf{0 . 0 6} \boldsymbol{m o l} \boldsymbol{L}^{-1}

\boldsymbol{B}=\mathbf{0 . 1 2} \boldsymbol{m o l} \boldsymbol{L}^{-1}

\boldsymbol{C}=\mathbf{0 . 2 1 6} \boldsymbol{m o l} \boldsymbol{L}^{-1}

Then

K_{c}

for the reaction is

Q6ChemistryUnit 6: Equilibrium

A flask containing 0.5 atm pressure of

A_{2}(g),

some solid

A B

added into flask which undergoes dissociation according to :

\boldsymbol{2} \boldsymbol{A} \boldsymbol{B}(\boldsymbol{s}) \rightleftharpoons \boldsymbol{A}_{2}(\boldsymbol{g})+\boldsymbol{B}_{2}(\boldsymbol{g})

\boldsymbol{K}_{\boldsymbol{p}}=\mathbf{0 . 0 6} \boldsymbol{a t m}^{2} .

The total pressure (in atm) at equilibrium is :

Q7ChemistryUnit 6: Equilibrium

What is the partial pressure (atm) of HI in the equilibrium mixture?

Q8ChemistryUnit 6: Equilibrium

Which is not a reversible reaction?

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