Chemistry · JEE

Equilibrium involving chemical processes: Law of chemical equilibrium, equilibrium constants (Kp and Kc) and their significance, the significance of Delta G and Delta G° in chemical equilibrium Concepts for JEE

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Master Equilibrium involving chemical processes: Law of chemical equilibrium, equilibrium constants (Kp and Kc) and their significance, the significance of Delta G and Delta G° in chemical equilibrium by understanding definitions, standard results, and typical JEE question patterns — then practise with syllabus-aligned MCQs on Goodmarks.

Build clear conceptual foundations for Equilibrium involving chemical processes: Law of chemical equilibrium, equilibrium constants (Kp and Kc) and their significance, the significance of Delta G and Delta G° in chemical equilibrium before speed practice. This guide covers what JEE expects and how to test yourself with MCQs.

Concept explainer

Equilibrium involving chemical processes: Law of chemical equilibrium, equilibrium constants (Kp and Kc) and their significance, the significance of Delta G and Delta G° in chemical equilibrium is a core JEE Main Chemistry subtopic under Equilibrium. Master the definitions, standard results, and typical MCQ patterns tested in JEE Main and Advanced.

Key points

Understand the definition and scope of Equilibrium involving chemical processes: Law of chemical equilibrium, equilibrium constants (Kp and Kc) and their significance, the significance of Delta G and Delta G° in chemical equilibrium in the JEE syllabus
Memorise key formulas and standard results linked to Equilibrium involving chemical processes: Law of chemical equilibrium, equilibrium constants (Kp and Kc) and their significance, the significance of Delta G and Delta G° in chemical equilibrium
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JEE tips

Revise Equilibrium involving chemical processes: Law of chemical equilibrium, equilibrium constants (Kp and Kc) and their significance, the significance of Delta G and Delta G° in chemical equilibrium with a one-page formula sheet before attempting mixed tests
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Students often rush Equilibrium involving chemical processes: Law of chemical equilibrium, equilibrium constants (Kp and Kc) and their significance, the significance of Delta G and Delta G° in chemical equilibrium questions without checking units, sign conventions, or boundary conditions — always verify assumptions before calculating.

Syllabus context

Part of Equilibrium in JEE Main Chemistry.

Free sample questions

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Q1ChemistryUnit 6: Equilibrium

One mole of ethanol is treated with one mole of ethanoic acid at

25 .

One-forth of the acid changes into ester at equilibrium. The equilibrium constant for the reaction will be:

Q2ChemistryUnit 6: Equilibrium

2 moles of

P C l_{5}

when heated in a closed vessels of 2 litre capacity at equilibrium

40 \%

P C l_{5}

dissociated in

P C l_{3}

and

C l_{2} .

What is the value of the equilibrium constant?

Q3ChemistryUnit 6: Equilibrium

56 \mathrm{g}

of nitrogen and

8 \mathrm{g}

of hydrogen gas are heated in a closed vessel. At equilibrium, 34 g of ammonia are present. The equilibrium number of moles of nitrogen, hydrogen and ammonia are respectively:

Q4ChemistryUnit 6: Equilibrium

A+B \rightleftharpoons C+D, K_{c}

for this reaction is 10. If 1,2,3,4 mole/litre of

A, B, C

and

D

respectively are present in a container at

25^{\circ} C,

the direction of reaction will be:

Q5ChemistryUnit 6: Equilibrium

For the system

\boldsymbol{A}_{(g)}+\mathbf{2} \boldsymbol{B}_{(\boldsymbol{g})} \rightleftharpoons \boldsymbol{C}_{(g)},

the equilibrium concentrations are

\boldsymbol{A}=\mathbf{0 . 0 6} \boldsymbol{m o l} \boldsymbol{L}^{-1}

\boldsymbol{B}=\mathbf{0 . 1 2} \boldsymbol{m o l} \boldsymbol{L}^{-1}

\boldsymbol{C}=\mathbf{0 . 2 1 6} \boldsymbol{m o l} \boldsymbol{L}^{-1}

Then

K_{c}

for the reaction is

Q6ChemistryUnit 6: Equilibrium

A flask containing 0.5 atm pressure of

A_{2}(g),

some solid

A B

added into flask which undergoes dissociation according to :

\boldsymbol{2} \boldsymbol{A} \boldsymbol{B}(\boldsymbol{s}) \rightleftharpoons \boldsymbol{A}_{2}(\boldsymbol{g})+\boldsymbol{B}_{2}(\boldsymbol{g})

\boldsymbol{K}_{\boldsymbol{p}}=\mathbf{0 . 0 6} \boldsymbol{a t m}^{2} .

The total pressure (in atm) at equilibrium is :

Q7ChemistryUnit 6: Equilibrium

What is the partial pressure (atm) of HI in the equilibrium mixture?

Q8ChemistryUnit 6: Equilibrium

Which is not a reversible reaction?

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