Physics · JEE

Online Practice: The potential energy of a spring, conservation of mechanical energy, conservative and non-conservative forces for JEE

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Q1PhysicsUnit 4: Work, Energy and Power
A single conservative force F(x)F(x) acts on a 1.0kg1.0-k g particle that moves along the x-axis. The potential energy U(x)U(x) is givenbyU(x)=20+(x2)2\operatorname{given} \operatorname{by} U(x)=20+(x-2)^{2} where xx is in meters. At x=5.0m,\boldsymbol{x}=\mathbf{5 . 0} \mathrm{m}, the particle has a kinetic energy of 20 J.What is the mechanical energy of the system?

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