Physics · JEE

Logic gates (OR, AND, NOT, NAND and NOR) Mock Test for JEE

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Q1PhysicsUnit 19: Electronic Devices
Braille is a based on _{-}-_{-}-_{-}- system.
Q2PhysicsUnit 19: Electronic Devices
When all the inputs of a NAND gate are connected together, the resulting circuit is:
Q3PhysicsUnit 19: Electronic Devices
A Truth table is given below. The logic gate having following truth table is ABYA \quad B \quad Y 011\begin{array}{lll}0 & 1 & 1\end{array} 000 \quad 0 0100 \quad 1 \quad 0 10
Q4PhysicsUnit 19: Electronic Devices
Which of the following applications is not based on use of ICs?
Q5PhysicsUnit 19: Electronic Devices
Assertion STATEMENT-1: If output of a AND gate is fed to OR gate, it is called NOR gate. Reason STATEMENT-2: If output of a AND gate is fed to NOT gate, it is called NAND gate.
Q6PhysicsUnit 19: Electronic Devices
The output of the given combination of gates is equivalent to:
Q7PhysicsUnit 19: Electronic Devices
The following circuit is equivalent to
Q8PhysicsUnit 19: Electronic Devices
Person who use boolean algebra for describing the operation of logic gates first was
Q9PhysicsUnit 19: Electronic Devices
Name the gate, which represents the Boolean expression Y=AB\boldsymbol{Y}=\boldsymbol{A} \cdot \boldsymbol{B}
Q10PhysicsUnit 19: Electronic Devices
What will be the input of AA and BB for Boolean expression (A+B)(AB)=1(\overline{A+B})(\overline{A \cdot B})=1
Q11PhysicsUnit 19: Electronic Devices
If a signal passing through a gate is inhibited by sending a LOW into one of the inputs, and the output is HIGH, the gate is a(n)a(n)
Q12PhysicsUnit 19: Electronic Devices
The minimum number of gates required to realise the expression Z=Z= DABC+DABCD A B C+D \overline{A B C} is
Q13PhysicsUnit 19: Electronic Devices
In Boolean algebra, A+B=Y\boldsymbol{A}+\boldsymbol{B}=\boldsymbol{Y} implies that
Q14PhysicsUnit 19: Electronic Devices
Which logic gates is represented by the following combination of logic gates?
Q15PhysicsUnit 19: Electronic Devices
Which of the following logic gates is an universal gate?

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