Physics · JEE

Alternating currents, peak and RMS value of alternating current/voltage Mock Test for JEE

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Syllabus context

Part of Electromagnetic Induction and Alternating Currents in JEE Main Physics.

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Q1PhysicsUnit 14: Electromagnetic Induction and Alternating Currents

Choose the incorrect statement.

Q2PhysicsUnit 14: Electromagnetic Induction and Alternating Currents

An alternating voltage given as

\boldsymbol{V}=

\mathbf{1 0 0} \sqrt{\mathbf{2}} \sin 100 t \quad

is applied to a capacitor of

1 \mu F

. The current reading of the ammeter will be equal to

\mathrm{mA}

Q3PhysicsUnit 14: Electromagnetic Induction and Alternating Currents

The average half-cycle value of a sine wave with a

40 V

peak is

Q4PhysicsUnit 14: Electromagnetic Induction and Alternating Currents

A sinusoidal voltage

V=200 \sin 314 t

is applied to a

10 \Omega

resistor. Find rms current

Q5PhysicsUnit 14: Electromagnetic Induction and Alternating Currents

An LC circuit has

L=5 \mathrm{mH}

and

C=20 \mu \mathrm{F}

\boldsymbol{v}=\mathbf{5} \times \mathbf{1 0}^{-\mathbf{3}}

coswt is supplied. is twice the resonant frequency. Find the maximum charge stored in the capacitor:

Q6PhysicsUnit 14: Electromagnetic Induction and Alternating Currents

In an a.c. circuit

\mathrm{V}

and I are given by

V=50 \sin 50 t

volt and

I=

100 \sin (50 t+\pi / 3) \mathrm{mA} .

The power dissipated in the circuit

Q7PhysicsUnit 14: Electromagnetic Induction and Alternating Currents

In a circuit the coil of a choke:

Q8PhysicsUnit 14: Electromagnetic Induction and Alternating Currents

The figure given shows the variation of an alternating emf with time. What is the average value of the emf for the shaded part of the graph?

Q9PhysicsUnit 14: Electromagnetic Induction and Alternating Currents

The dielectric strength of air is

3 \times 10^{6} v

/ \mathrm{m} .

A parallel plate air capacitor has

\operatorname{area} 20 c m^{2}

and plate separation

1 \mathrm{mm}

Then maximum r.m.s. voltage of an A.C. source which can be safely connected to this capacitor is

Q10PhysicsUnit 14: Electromagnetic Induction and Alternating Currents

The equation of an alternating voltage is

V=100 \sqrt{2} \sin 100 \pi t

volt. The RMS value of voltage and frequency will be respectively

Q11PhysicsUnit 14: Electromagnetic Induction and Alternating Currents

The instantaneous voltage through a device of impedence

20 \Omega

e=

80 \sin 100 \pi t .

The effective value of the current is

Q12PhysicsUnit 14: Electromagnetic Induction and Alternating Currents

A steady current of magnitude

I

and an

A C

current of peak value

I

are allowed to pass through identical resistor for the same time. The ratio of heat produced in the two resistors will be :

Q13PhysicsUnit 14: Electromagnetic Induction and Alternating Currents

In an A.C. circuit, the current flowing in inductance is

\boldsymbol{I}=\mathbf{5} \sin (\mathbf{1 0 0} \boldsymbol{t}-\boldsymbol{\pi} / \mathbf{2})

ampers and the potential difference is

=200 \sin (100 \mathrm{t})

volts. The power consumption is equal to

Q14PhysicsUnit 14: Electromagnetic Induction and Alternating Currents

If the input frequency of a full wave rectifier is

50 H z

ac. Its output frequency is

Q15PhysicsUnit 14: Electromagnetic Induction and Alternating Currents

In a black box of unknown elements

(\boldsymbol{L}

R

or any other combination), an ac voltage

\boldsymbol{E}=\boldsymbol{E}_{0} \sin (\boldsymbol{\omega} \boldsymbol{t}+\boldsymbol{\phi})

is applied and current in the circuit was found to be

\boldsymbol{I}=\boldsymbol{I}_{0} \sin [\boldsymbol{\omega} \boldsymbol{t}+\boldsymbol{\phi}+(\boldsymbol{\pi} / \mathbf{4})] .

Then the unknown elements in the box may be

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