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Scalar and vector products Revision for JEE

17+ syllabus-aligned questions available

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Revise Scalar and vector products by covering every subtopic once, drilling formulas, then solving 17+ timed MCQs with full solutions.

Use this Scalar and vector products revision checklist before mocks and the final exam. Reinforce concepts with 17+ syllabus-aligned MCQs on Goodmarks.

Revision checklist

  1. 1.Core idea: Scalar and vector products
  2. 2.Relates to other subtopics in Vector Algebra
  3. 3.Vector components in 2D and 3D
  4. 4.Scalar and vector products
  5. 5.Master Scalar and vector products definitions and standard results
  6. 6.Solve 20 timed MCQs for Scalar and vector products

Syllabus context

Part of Vector Algebra in JEE Main Mathematics.

Free sample questions

Attempt 8 free MCQs for Scalar and vector products. Unlock 9+ more with Pro.

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Q1MathsUnit 12: Vector Algebra
Let a,β,γa, \beta, \gamma be distinct real numbers. The points with position vectors ai +βj++\beta j+ γk,βi+γj+ak,γi+aj+βk\gamma k, \beta i+\gamma j+a k, \gamma i+a j+\beta k
Q2MathsUnit 12: Vector Algebra
The non zero vector a⃗,b⃗,c⃗\vec{a}, \vec{b}, \vec{c} related by a⃗=8b⃗\vec{a}=8 \vec{b} and c⃗=−7b⃗,\vec{c}=-7 \vec{b}, then angle between a⃗&c⃗\vec{a} \& \vec{c} is
Q3MathsUnit 12: Vector Algebra
Consider ΔABC\Delta A B C with A≡(a⃗),B≡(b⃗)A \equiv(\vec{a}), B \equiv(\vec{b}) and C=(c⃗),C=(\vec{c}), ff b⃗.(a⃗+c⃗)=b⃗⋅b⃗+\vec{b} .(\vec{a}+\vec{c})=\vec{b} \cdot \vec{b}+ a⃗⋅c⃗;∣b⃗−a⃗∣=3;∣c⃗−b⃗∣=4\vec{a} \cdot \vec{c} ;|\vec{b}-\vec{a}|=3 ;|\vec{c}-\vec{b}|=4 then the angle between the medians AM‾\overline{A M} and BDB D is
Q4MathsUnit 12: Vector Algebra
If position vectors of four vertices of a square are A=3i−λj,B=9i−6k\boldsymbol{A}=\mathbf{3} \boldsymbol{i}-\boldsymbol{\lambda} \boldsymbol{j}, \boldsymbol{B}=\mathbf{9} \boldsymbol{i}-\boldsymbol{6} \boldsymbol{k} C=6j−5k\boldsymbol{C}=\mathbf{6} \boldsymbol{j}-\mathbf{5} \boldsymbol{k} and D=αi−3j+4k\boldsymbol{D}=\boldsymbol{\alpha} \boldsymbol{i}-\boldsymbol{3} \boldsymbol{j}+\boldsymbol{4} \boldsymbol{k} then value of λ−α\lambda-\alpha is :
Q5MathsUnit 12: Vector Algebra
For any four points P,Q,R,SP, Q, R, S ∣PQ→×R→S−QR→×P→S+R→P×Q→S∣|\overrightarrow{P Q} \times \overrightarrow{\boldsymbol{R}} \boldsymbol{S}-\overrightarrow{\boldsymbol{Q} \boldsymbol{R}} \times \overrightarrow{\boldsymbol{P}} \boldsymbol{S}+\overrightarrow{\boldsymbol{R}} \boldsymbol{P} \times \overrightarrow{\boldsymbol{Q}} \boldsymbol{S}| is equal to 4 times the area of the triangle.
Q6MathsUnit 12: Vector Algebra
If A=(1,2,3),B=(2,3,4)\boldsymbol{A}=(\mathbf{1}, \mathbf{2}, \mathbf{3}), \boldsymbol{B}=(\mathbf{2}, \mathbf{3}, \mathbf{4}) and AB\boldsymbol{A} \boldsymbol{B} is produced upto CC such that 2AB=BC2 A B=B C then C=C=
Q7MathsUnit 12: Vector Algebra
If a,b,ca, b, c are non-coplanar vectors and λ\lambda is a real number, then [λ(a⃗+b⃗)λ2b⃗λc⃗]=[a⃗b⃗+c⃗b⃗]\left[\lambda(\vec{a}+\vec{b}) \lambda^{2} \vec{b} \lambda \vec{c}\right]=[\vec{a} \quad \vec{b}+\vec{c} \quad \vec{b}] for
Q8MathsUnit 12: Vector Algebra
The points A(−1,3,0),B(2,2,1)A(-1,3,0), B(2,2,1) and C(1,1,3)C(1,1,3) determine a plane. The distance of the plane A,B,CA, B, C from the point D(5,7,8)D(5,7,8) is

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How should I revise Scalar and vector products before JEE?

Follow the checklist on this page, revise formulas daily, and attempt mixed MCQs every 2–3 days.

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