Mathematics · JEE

Easy Inverse functions MCQs for JEE

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Syllabus context

Part of Limit, Continuity and Differentiability in JEE Main Mathematics.

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Q1MathsUnit 7: Limit, Continuity and Differentiability

f(x)=x^{2}-x+5, x>\frac{1}{2},

and

g(x)

is its inverse function, then

g^{\prime}(7)

equals:

Q2MathsUnit 7: Limit, Continuity and Differentiability

The domain of

\mathbf{f}(\mathbf{x})=

\cot ^{-1}\left(\frac{\mathbf{x}}{\sqrt{\mathbf{x}^{2}-\left[\mathbf{x}^{2}\right]}}\right)

([.]

denotes the greatest integer function)

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