Mathematics · JEE

Derivatives of order upto two Short Tricks for JEE

1+ syllabus-aligned questions available

Quick answer

Short tricks for Derivatives of order upto two work only with strong fundamentals. Apply the tips below in timed sets and review every explanation.

Use these Derivatives of order upto two shortcuts to save time in JEE Mathematics papers — then validate speed with 1+ MCQs on Goodmarks.

Short tricks for speed

  • Derivatives of order upto two focus drill

    Solve 15 mixed MCQs for Derivatives of order upto two, review every explanation, and note formulas you hesitated on.

  • Calculus substitution scan

    Spot standard forms (sin²x, 1/(a²+x²), e^ax) before integrating — JEE rewards pattern recognition.

  • Graph sketch shortcut

    For coordinate geometry, mark intercepts and asymptotes first; many MCQs need only qualitative graph features.

Free sample questions

Attempt 1 free MCQs for Derivatives of order upto two. Unlock the full bank with Pro.

Unlock full bank
Q1MathsUnit 7: Limit, Continuity and Differentiability
Assertion(A): Let f(x)\boldsymbol{f}(\boldsymbol{x}) be twice differentiable function such that f(x)=f(x)\boldsymbol{f}^{\prime \prime}(\boldsymbol{x})=-\boldsymbol{f}(\boldsymbol{x}) and f(x)=g(x).\boldsymbol{f}^{\prime}(\boldsymbol{x})=\boldsymbol{g}(\boldsymbol{x}) . If h(x)=[f(x)]2+[g(x)]2\boldsymbol{h}(\boldsymbol{x})=[\boldsymbol{f}(\boldsymbol{x})]^{2}+[\boldsymbol{g}(\boldsymbol{x})]^{2} and h(1)=8\boldsymbol{h}(\mathbf{1})=\mathbf{8} thenh(2)=8\operatorname{then} h(2)=8 Reason (R): Derivative of a constant function is zero.

Want unlimited Derivatives of order upto two practice?

Pro unlocks the full question bank, topic filters, and attempt history.

Frequently asked questions

Are short tricks enough for Derivatives of order upto two in JEE?

No — tricks complement concepts. Master the theory first, then use shortcuts in timed MCQ practice.