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Mathematics · JEE

Integration by substitution, by parts and by partial fractions Concepts for JEE

3+ syllabus-aligned questions available

Quick answer

Master Integration by substitution, by parts and by partial fractions by understanding definitions, standard results, and typical JEE question patterns — then practise with syllabus-aligned MCQs on Goodmarks.

Build clear conceptual foundations for Integration by substitution, by parts and by partial fractions before speed practice. This guide covers what JEE expects and how to test yourself with MCQs.

Concept explainer

Integration by substitution, by parts and by partial fractions is a core JEE Main Mathematics subtopic under Integral Calculus. Master the definitions, standard results, and typical MCQ patterns tested in JEE Main and Advanced.

Key points

  • Understand the definition and scope of Integration by substitution, by parts and by partial fractions in the JEE syllabus
  • Memorise key formulas and standard results linked to Integration by substitution, by parts and by partial fractions
  • Practise 20–40 syllabus-aligned MCQs with step-by-step solutions

JEE tips

  • Revise Integration by substitution, by parts and by partial fractions with a one-page formula sheet before attempting mixed tests
  • After each practice set, log mistakes specific to Integration by substitution, by parts and by partial fractions and reattempt after 48 hours

Common trap

Students often rush Integration by substitution, by parts and by partial fractions questions without checking units, sign conventions, or boundary conditions — always verify assumptions before calculating.

Syllabus context

Part of Integral Calculus in JEE Main Mathematics.

Free sample questions

Attempt 3 free MCQs for Integration by substitution, by parts and by partial fractions. Unlock the full bank with Pro.

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Q1MathsUnit 8: Integral Calculus
x+2x3−x=\frac{\boldsymbol{x}+\mathbf{2}}{\boldsymbol{x}^{\boldsymbol{3}}-\boldsymbol{x}}=
Q2MathsUnit 8: Integral Calculus
∫(tan⁡10x+tan⁡12x)dx=\int\left(\tan ^{10} x+\tan ^{12} x\right) d x=
Q3MathsUnit 8: Integral Calculus
∫(sin⁡x)99(cos⁡x)−101dx=−…−C\int(\sin x)^{99}(\cos x)^{-101} d x=_{-} \ldots-C_{ }

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Focus on core ideas across Integration by substitution, by parts and by partial fractions. JEE tests application, not just memorisation.

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