Mathematics · JEE

Hard Relations between roots and coefficients, nature of roots MCQs for JEE

12+ syllabus-aligned questions available

Quick answer

Hard Relations between roots and coefficients, nature of roots MCQs train multi-concept problem solving — attempt after mastering easy and medium sets (12+ on Goodmarks).

Push your limits with hard Relations between roots and coefficients, nature of roots MCQs designed for JEE Advanced-level thinking. 12+ questions with detailed solutions.

Free sample questions

Attempt 8 free MCQs for Relations between roots and coefficients, nature of roots. Unlock 4+ more with Pro.

Unlock full bank
Q1MathsUnit 2: Complex Numbers and Quadratic Equations
If x+1x=4,x+\frac{1}{x}=4, then x4+1x4x^{4}+\frac{1}{x^{4}} is equal to
Q2MathsUnit 2: Complex Numbers and Quadratic Equations
If the product of two numbers is 10 and their sum is 7,7, which is the greatest of the two numbers?
Q3MathsUnit 2: Complex Numbers and Quadratic Equations
The zeros of the polynomial n3+9n2+n^{3}+9 n^{2}+ 23n+1523 n+15 are ad,aa-d, a and a+d.a+d . What is the value of 'a'?
Q4MathsUnit 2: Complex Numbers and Quadratic Equations
Discriminant of the equation 3x2+-3 x^{2}+ 2x8=02 x-8=0 is
Q5MathsUnit 2: Complex Numbers and Quadratic Equations
If the sum of the roots of the equation ax2+bx+c=0a x^{2}+b x+c=0 is equal to sum of the squares of their reciprocals, then bc2,ca2,ab2b c^{2}, c a^{2}, a b^{2} are in
Q6MathsUnit 2: Complex Numbers and Quadratic Equations
If xy=7x-y=7 and x3y3=133;x^{3}-y^{3}=133 ; find: the value of xyx y
Q7MathsUnit 2: Complex Numbers and Quadratic Equations
Find pRp \in R for x2px+p+3=0x^{2}-p x+p+3=0 has
Q8MathsUnit 2: Complex Numbers and Quadratic Equations
Assertion Let equations ax2+bx+c=a x^{2}+b x+c= 0(a,b,cR)&x2+2x+5=0\mathbf{0}(\boldsymbol{a}, \boldsymbol{b}, \boldsymbol{c} \in \boldsymbol{R}) \& \boldsymbol{x}^{2}+\mathbf{2} \boldsymbol{x}+\mathbf{5}=\mathbf{0} have common root, then a+cb=13\frac{\boldsymbol{a}+\boldsymbol{c}}{\boldsymbol{b}}=\frac{\mathbf{1}}{\mathbf{3}} Reason If both roots of Ax2+Bx+K1=0&A x^{2}+B x+K_{1}=0 \& Ax2+Bx+K2=0\boldsymbol{A}^{\prime} \boldsymbol{x}^{2}+\boldsymbol{B}^{\prime} \boldsymbol{x}+\boldsymbol{K}_{2}=\mathbf{0} are identical thenAA1=BB1=K1K2( where A,B,K1\operatorname{then} \frac{\boldsymbol{A}}{\boldsymbol{A}_{1}}=\frac{\boldsymbol{B}}{\boldsymbol{B}_{1}}=\frac{\boldsymbol{K}_{1}}{\boldsymbol{K}_{2}}\left(\text { where } \boldsymbol{A}, \boldsymbol{B}, \boldsymbol{K}_{1}\right. and A,B,K2R)\left.A^{\prime}, B,^{\prime} K_{2} \in R\right)

Want unlimited Relations between roots and coefficients, nature of roots practice?

Pro unlocks the full question bank, topic filters, and attempt history.

Frequently asked questions

When should I attempt hard Relations between roots and coefficients, nature of roots MCQs?

After 70%+ accuracy on medium MCQs and once core formulas are automatic.