Chemistry · JEE

Medium Laws of chemical combination, Atomic and molecular masses MCQs for JEE

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Medium Laws of chemical combination, Atomic and molecular masses MCQs bridge basics and advanced JEE problems — 14+ available on Goodmarks.

Medium-difficulty Laws of chemical combination, Atomic and molecular masses MCQs mirror typical JEE Main questions. Practise 14+ MCQs with step-by-step solutions.

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Part of Some Basic Concepts in Chemistry in JEE Main Chemistry.

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Q1ChemistryUnit 1: Some Basic Concepts in Chemistry

Who proposed that equal volumes of gases at the same temperature and pressure have same number of molecules.

Q2ChemistryUnit 1: Some Basic Concepts in Chemistry

A pair of compounds which is an illustration of law of multiple proportions is:

Q3ChemistryUnit 1: Some Basic Concepts in Chemistry

Carbon and oxygen forms two compounds. Carbon content in one of them is

42.9 \%

while in the other is 27.3\%. The given data is in support with:

Q4ChemistryUnit 1: Some Basic Concepts in Chemistry

3 volumes of hydrogen are required to combine with one volume of nitrogen to form 2 volumes of ammonia. When 1 mole of hydrogen is allowed to react with the mole of nitrogen, the two gases?

Q5ChemistryUnit 1: Some Basic Concepts in Chemistry

Assertion Pure water obtained from different states of India always contains hydrogen and oxygen in the ratio of 1: 8 by mass. Reason Total mass of reactants and products during chemical change is always the same.

Q6ChemistryUnit 1: Some Basic Concepts in Chemistry

Chemical compounds are formed to have constant composition irrespective of their This question has multiple correct options

Q7ChemistryUnit 1: Some Basic Concepts in Chemistry

Zinc sulphate contains

22.65 \% \mathrm{Zn}

and

43.9 \% H_{2} O .

If the law of constant proportions is true, then the mass of zinc required to give 40 g crystals will be:

Q8ChemistryUnit 1: Some Basic Concepts in Chemistry

16.8 \mathrm{g}

of metal carbonate on thermal decomposition gave 8 g of metallic oxide and

8.8 \mathrm{g}

of carbon dioxide. They follow:

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