Chemistry · JEE

Emf of a Galvanic cell and its measurement, Nernst equation and its applications, relationship between cell potential and Gibbs' energy change Short Tricks for JEE

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Q1ChemistryUnit 7: Redox Reactions and Electrochemistry
Which of the following changes will cause the free energy of a cell reaction to decrease? ZnZnSO4(aq)(x1M)HCl(aq)(x2N\boldsymbol{Z} \boldsymbol{n} \mid \boldsymbol{Z} \boldsymbol{n} \boldsymbol{S} \boldsymbol{O}_{4}(\boldsymbol{a} \boldsymbol{q})\left(\boldsymbol{x}_{1} \boldsymbol{M}\right) \| \boldsymbol{H} \boldsymbol{C l}(\boldsymbol{a} \boldsymbol{q})\left(\boldsymbol{x}_{2} \boldsymbol{N}\right. This question has multiple correct options
Q2ChemistryUnit 7: Redox Reactions and Electrochemistry
Assertion In the Daniel cell, if concentration of Cu2+C u^{2+} and Zn2+Z n^{2+} ions are doubled, the emf of the cell will not change. Reason f the concentration of ions in contact with the metals is doubled, the electrode potential is doubled.
Q3ChemistryUnit 7: Redox Reactions and Electrochemistry
For the reaction: Fe2+(aq)+Ag+(aq)Ag(s)+\boldsymbol{F} \boldsymbol{e}^{2+}(\boldsymbol{a} \boldsymbol{q})+\boldsymbol{A} \boldsymbol{g}^{+}(\boldsymbol{a} \boldsymbol{q}) \longrightarrow \boldsymbol{A} \boldsymbol{g}(\boldsymbol{s})+ Fe+3(aq)\boldsymbol{F} \boldsymbol{e}^{+\boldsymbol{3}}(\boldsymbol{a} \boldsymbol{q}) Predict which change will decrease the cell voltage?
Q4ChemistryUnit 7: Redox Reactions and Electrochemistry
Calculate Ecell\boldsymbol{E}_{\text {cell}} Pt(s)H2(g)1atmHA(Ka=107)1MHB(k\boldsymbol{P t}(\boldsymbol{s})\left|\boldsymbol{H}_{2}(\boldsymbol{g})_{1 a t m}\right| \boldsymbol{H} \boldsymbol{A}_{\left(\boldsymbol{K}_{a}=10^{-7}\right)} \mathbf{1} \boldsymbol{M} \| \boldsymbol{H} \boldsymbol{B}_{(\boldsymbol{k}}
Q5ChemistryUnit 7: Redox Reactions and Electrochemistry
The standard cell potential for ZnZn2+Cu2+CuZ n\left|Z n^{2+}\right|\left|C u^{2+}\right| C u is 1.10V.1.10 V . When the cell is completely discharged, log[Zn2+]/[Cu2+]\log \left[Z n^{2+}\right] /\left[C u^{2+}\right] is closest to:
Q6ChemistryUnit 7: Redox Reactions and Electrochemistry
The standard oxidation potential of Zn referred to SHE is 0.76V0.76 \mathrm{V} and that of Cu\mathrm{Cu} is 0.34V-0.34 V at 25C.25^{\circ} \mathrm{C} . When excess of Zn is added to CuSO4,ZnC u S O_{4}, Z n displaces Cu2+C u^{2+} till equilibrium is reached. What is the ratio of Zn2+Z n^{2+} to Cu2+C u^{2+} ions at equilibrium? Express the ans in the form [Zn2+]/[Cu2+]=k×1037,\left[Z n^{2+}\right] /\left[C u^{2+}\right]=k \times 10^{37}, and find kk
Q7ChemistryUnit 7: Redox Reactions and Electrochemistry
The equilibrium constant for the reaction Sr(s)+Mg+2(aq)Sr+2(aq)+\boldsymbol{S} \boldsymbol{r}(\boldsymbol{s})+\boldsymbol{M} \boldsymbol{g}^{+2}(\boldsymbol{a} \boldsymbol{q}) \rightleftharpoons \boldsymbol{S} \boldsymbol{r}^{+2}(\boldsymbol{a} \boldsymbol{q})+ Mg(s)M g(s) is 4×10124 \times 10^{12} at 25C25^{\circ} C The EoE^{o} for a cell made up of the SrSr+2\boldsymbol{S} \boldsymbol{r} \mid \boldsymbol{S} \boldsymbol{r}^{+2} and Mg+2Mg\boldsymbol{M} \boldsymbol{g}^{+2} \mid \boldsymbol{M} \boldsymbol{g} half cells (log(\log 2=0.3)\mathbf{2}=\mathbf{0 . 3})
Q8ChemistryUnit 7: Redox Reactions and Electrochemistry
The EcellE_{\text {cell}} for a given cell is 1.2346 and 1.2340V1.2340 V at 300K300 \mathrm{K} and 310K310 \mathrm{K} respectively. Calculate the change in entropy during the cell reaction if the redox change involves three electrons.

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