Chemistry · JEE

Ionization of water, pH scale, common ion effect, hydrolysis of salts and pH of their solutions, the solubility of sparingly soluble salts, solubility products and buffer solutions Mock Test for JEE

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Syllabus context

Part of Equilibrium in JEE Main Chemistry.

Free sample questions

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Q1ChemistryUnit 6: Equilibrium

100ml of a solution of HCl with pH value 3 is diluted with

400 \mathrm{ml}

of water. The new pH of the solution is?

Q2ChemistryUnit 6: Equilibrium

A solution contains

10 \mathrm{mL}

0.1 \mathrm{N}

NaOH and

10 \mathrm{mL}

0.05 \mathrm{Na}_{2} \mathrm{SO}_{4} .

pH of this solution is

Q3ChemistryUnit 6: Equilibrium

K_{a}

for acetic acid in water is

1.7 \times

10^{-5}

25^{\circ} \mathrm{C} .

The

\mathrm{pH}

of a mixture of 25

\mathrm{ml}

0.02 \mathrm{N}

acetic acid and

2.5 \mathrm{ml}

of 0.1N NaOH (neglecting volume change) will be

(\log 1.7=0.23)

Q4ChemistryUnit 6: Equilibrium

A solution having hydrogen ion concentration is

0.0005 g

eqvt/litre, its

p O H

Q5ChemistryUnit 6: Equilibrium

Assertion At

25^{\circ} C

, the pH of

10^{-8} M

HClis 8 Reason pH of acidic solution is always below 7

\operatorname{at} 25^{\circ} C

Q6ChemistryUnit 6: Equilibrium

p H

of water is 7 when any substance

Y

is dissolved in water then

p H

becomes 13. Substance

Y

is a salt of:

Q7ChemistryUnit 6: Equilibrium

Oxides of sulphur present in the atmosphere are washed down by rain and would result in:

Q8ChemistryUnit 6: Equilibrium

The pH of

D_{2} O

and

H_{2} O

298 \mathrm{K}

is:

Q9ChemistryUnit 6: Equilibrium

Maximum change in

p H

is observed when 50 of

1 M K O H

solution is added to

Q10ChemistryUnit 6: Equilibrium

Assertion Assertion: A solution of

N H_{4} C l

in water is acidic in nature. Reason Reason : Ammoniun ions undergo hydrolysis to form

N H_{4} O H

Q11ChemistryUnit 6: Equilibrium

1.2 mol of

\boldsymbol{C H}_{3} \boldsymbol{N} \boldsymbol{H}_{2}\left(\boldsymbol{p} \boldsymbol{K}_{\boldsymbol{b}}=\boldsymbol{3} . \boldsymbol{3}\right)

is added to 0.8 moles of

H C l

and the solution is diluted to one litre, resulting

\boldsymbol{p} \boldsymbol{H}

of solution is:

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