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Easy Delta G° (Standard Gibbs energy change) and equilibrium constant MCQs for JEE

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Part of Chemical Thermodynamics in JEE Main Chemistry.

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Q1ChemistryUnit 4: Chemical Thermodynamics

The plot shows the variation of

-\ln \boldsymbol{K}_{\boldsymbol{p}}

versus temperature for the two reactions.

M(s)+\frac{1}{2} O_{2}(g) \rightarrow M O(s)

and

C(s)+\frac{1}{2} O_{2}(g) \rightarrow C O(s)

Identify the correct statement?

Q2ChemistryUnit 4: Chemical Thermodynamics

toppr Q Type your question At the point of intersection of

A l_{2} U_{3}

and

M g O

curves

(A), \triangle G^{0}

becomes zero for the reaction,

\frac{2}{3} A l_{2} O_{3}+2 M g \rightarrow+\frac{4}{3} A l

Below this point, magnesium can reduce alumina. Although thermodynamically feasible, Al is not used for reduction of

M g O

because:

Q3ChemistryUnit 4: Chemical Thermodynamics

A schematic plot of

\ln \boldsymbol{K}_{e q}

. versus inverse of temperature for a reaction is shown below: The reaction must be:

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