Chemistry · JEE

Elementary and complex reactions, order and molecularity of reactions, rate law, rate constant and its units Concepts for JEE

7+ syllabus-aligned questions available

Quick answer

Master Elementary and complex reactions, order and molecularity of reactions, rate law, rate constant and its units by understanding definitions, standard results, and typical JEE question patterns — then practise with syllabus-aligned MCQs on Goodmarks.

Build clear conceptual foundations for Elementary and complex reactions, order and molecularity of reactions, rate law, rate constant and its units before speed practice. This guide covers what JEE expects and how to test yourself with MCQs.

Concept explainer

Elementary and complex reactions, order and molecularity of reactions, rate law, rate constant and its units is a core JEE Main Chemistry subtopic under Chemical Kinetics. Master the definitions, standard results, and typical MCQ patterns tested in JEE Main and Advanced.

Key points

Understand the definition and scope of Elementary and complex reactions, order and molecularity of reactions, rate law, rate constant and its units in the JEE syllabus
Memorise key formulas and standard results linked to Elementary and complex reactions, order and molecularity of reactions, rate law, rate constant and its units
Practise 20–40 syllabus-aligned MCQs with step-by-step solutions

JEE tips

Revise Elementary and complex reactions, order and molecularity of reactions, rate law, rate constant and its units with a one-page formula sheet before attempting mixed tests
After each practice set, log mistakes specific to Elementary and complex reactions, order and molecularity of reactions, rate law, rate constant and its units and reattempt after 48 hours

Common trap

Students often rush Elementary and complex reactions, order and molecularity of reactions, rate law, rate constant and its units questions without checking units, sign conventions, or boundary conditions — always verify assumptions before calculating.

Syllabus context

Part of Chemical Kinetics in JEE Main Chemistry.

Free sample questions

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Q1ChemistryUnit 8: Chemical Kinetics

A reaction

A+B \rightarrow C

is second order with respect to

A

and independent of

B

The rate expression for the reaction is:

Q2ChemistryUnit 8: Chemical Kinetics

Statement - I : The molecularity of the reaction

\boldsymbol{H}_{2}+\boldsymbol{B} \boldsymbol{r}_{2} \rightarrow 2 \mathrm{HBr}

is 2 Statement - II: The order of this reaction is

3 / 2

Q3ChemistryUnit 8: Chemical Kinetics

The choices below are some of the proposed steps of a reaction mechanism. Which step is least likely to be the ratedetermining step of the mechanism?

Q4ChemistryUnit 8: Chemical Kinetics

Which one of the following statements for order of reaction is not correct?

Q5ChemistryUnit 8: Chemical Kinetics

In the hydrolysis of organic chloride in the presence of a large excess of water,

\boldsymbol{R C l}+\boldsymbol{H}_{2} \boldsymbol{O} \rightarrow \boldsymbol{R O H}+\boldsymbol{H} \boldsymbol{C l}

Q6ChemistryUnit 8: Chemical Kinetics

For the reaction given below,

\mathbf{2} \mathbf{O}_{\mathbf{3}}(\mathbf{g}) \rightarrow \mathbf{3} \mathbf{O}_{\mathbf{2}}(\mathbf{g})

\operatorname{Step} \mid: \mathbf{O}_{3}(\mathbf{g}) \rightarrow \mathbf{O}_{2}(\mathbf{g})+\mathbf{O}(\mathbf{g})

Step

2: \mathrm{O}_{3}(\mathrm{g})+\mathrm{O} \rightarrow^{\text {slow }} 2 \mathrm{O}_{2}(\mathrm{g})

Statement I: The molecularity of the first step is 1 and of the second step is 2 Statement-II:

O(g)

is an intermediate and rate of reaction is

\mathbf{K}\left[\mathbf{O}_{3}\right]^{2}\left[\mathbf{O}_{2}\right]^{-1}

and order of reaction is 1

Q7ChemistryUnit 8: Chemical Kinetics

Which of the following statement is true for the reaction,

\boldsymbol{H}_{2}+\boldsymbol{B} \boldsymbol{r}_{2} \rightarrow \boldsymbol{2} \boldsymbol{H} \boldsymbol{B} \boldsymbol{r}

The rate law is

\frac{\boldsymbol{d} \boldsymbol{x}}{\boldsymbol{d} \boldsymbol{t}}=\boldsymbol{k}\left[\boldsymbol{H}_{2}\right]\left[\boldsymbol{B} \boldsymbol{r}_{2}\right]^{1 / 2}

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Frequently asked questions

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