Maths · Calculation of standard deviation, variance and mean deviation for grouped and ungrouped data
The variance of observations 112,116,120,125,132 is
The variance of observations 112,116,120,125,132 is
- A. 58.8
- B. 48.8
- C. 61.8
- D. None of these
Step-by-step solution
Mean = (112+116+120+125+132)/5 = 121. Squared deviations: (112-121)^2=81, (116-121)^2=25, (120-121)^2=1, (125-121)^2=16, (132-121)^2=121. Sum = 244. Variance = 244/5 = 48.8.
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