Maths · Union, intersection and complement of sets and their algebraic properties
f =50, n(A)=20, n\left((A \cup B)^{\prime}\right)=18 \) then \) is
f \( n(U)=50, n(A)=20, n\left((A \cup B)^{\prime}\right)=18 \) then \( n(B-A) \) is
- A. 14
- B. 12
- C. 16
- D. 20
Step-by-step solution
n(U)=50, n((A∪B)')=18 ⇒ n(A∪B)=50-18=32. n(A∪B)=n(A)+n(B)-n(A∩B)=20+n(B)-n(A∩B)=32 ⇒ n(B)-n(A∩B)=12. But n(B-A)=n(B)-n(A∩B)=12.
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