Maths · The fundamental principle of counting
In how many ways is it possible to choose a white square and a black square on a
In how many ways is it possible to choose a white square and a black square on a chessboards, so that the squares must not lie in the same row or column?
- A. 56
- B. 896
- C. 60
- D. 768
Step-by-step solution
Total white squares = 32, total black squares = 32. For a given white square, black squares in the same row = 4, in the same column = 4 (disjoint), so valid black squares = 32 - 8 = 24. Total ways = 32 * 24 = 768. Alternatively, total pairs = 32*32 = 1024, subtract pairs sharing row (8 rows * 4*4 = 128) and sharing column (128) to get 1024 - 256 = 768.
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