Maths · Area of triangles using determinants
When the base of a triangle is increased by and the altitude to this base is dec
When the base of a triangle is increased by \( 10 \% \) and the altitude to this base is decreased by \( 10 \% \), the change in area is
- A. \( 1 \% \) increase
- B. \( \frac{1}{2} \% \) increase
- C. 0 \% \)
- D. \( 1 \% \) decrease
Step-by-step solution
Let original base = b and altitude = h. Original area = (1/2)bh. New base = 1.1b, new altitude = 0.9h. New area = (1/2)(1.1b)(0.9h) = 0.99 * (1/2)bh. So area decreases by 1%.
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