Maths · Evaluation of definite integrals
Evaluate:
Evaluate: \( \int_{1}^{2} \log x d x \)
- A. \( 2 \log 2-1 \)
- B. \( \log 2-1 \)
- C. \( 2 \log 2+1 \)
- D. \( \log 2-2 \)
Step-by-step solution
∫ log x dx = x log x - x + C. Evaluating from 1 to 2: (2 log 2 - 2) - (1*0 - 1) = 2 log 2 - 2 + 1 = 2 log 2 - 1.