Maths · Sections of conics, equations of conic sections (parabola, ellipse and hyperbola) in standard forms

Triangle is inscribed in the parabola described by the equation so that is the v

Triangle \( A B C \) is inscribed in the parabola described by the equation \( y^{2}-6 x-4 y+10=0 \) so that \( A \) is the vertex of the parabola and \( B \) and \( C \) are the end points of the latus rectum of the parabola. The area of triangle \( A B C \) is

  • A. 18
  • B. 9
  • C. 4 .5 \)
  • D. 2.25

Step-by-step solution

Rewrite the parabola equation as (y-2)^2 = 6(x-1). Vertex A is (1,2), a=1.5, focus (2.5,2). Latus rectum endpoints B(2.5,5) and C(2.5,-1). Base BC length = 6, height from A to line x=2.5 is 1.5, area = 0.5*6*1.5 = 4.5.
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