Maths · Distance formula, sections formula, locus and its equation
The point X-axis which is equidistant from the point (3,5) and (4,2) is
The point X-axis which is equidistant from the point (3,5) and (4,2) is
- A. (-6,0)
- B. (-7, 0)
- C. (7, 0)
- D. (-5, 0)
Step-by-step solution
Let the point on x-axis be (x, 0). Using distance formula: √((x-3)²+5²) = √((x-4)²+2²). Squaring gives (x-3)²+25 = (x-4)²+4. Expanding: x²-6x+9+25 = x²-8x+16+4 → -6x+34 = -8x+20 → 2x = -14 → x = -7. Thus point is (-7, 0).
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