Maths · The slope of a line, parallel and perpendicular lines
An equation for the line that passes through (10,-1) and is perpendicular to is
An equation for the line that passes through (10,-1) and is perpendicular to \( y=\frac{x^{2}}{4}-2 \) is
- A. \( 4 x+y=39 \)
- B. \( 2 x+y=19 \)
- C. \( x+y=9 \)
- D. \( x+2 y=8 \)
Step-by-step solution
Given equation is likely a misprint and should be y = x/4 - 2, a line with slope 1/4. A perpendicular line has slope -4. Using point-slope form through (10,-1): y + 1 = -4(x-10) => y = -4x + 39 => 4x + y = 39.
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