Maths · Binomial theorem for a positive integral index
Using the formula for squaring a binomial the value of ^{2} \) is:
Using the formula for squaring a binomial the value of \( (999)^{2} \) is:
- A. 98009
- B. 998005
- C. 998001
- D. 998002
Step-by-step solution
We use the formula (a - b)^2 = a^2 - 2ab + b^2. Write 999 as 1000 - 1. Then (1000 - 1)^2 = 1000^2 - 2*1000*1 + 1^2 = 1000000 - 2000 + 1 = 998001.