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Trigonometry Concepts for JEE

42+ syllabus-aligned questions available

Quick answer

Master Trigonometry by understanding definitions, standard results, and typical JEE question patterns — then practise with syllabus-aligned MCQs on Goodmarks.

Build clear conceptual foundations for Trigonometry before speed practice. This guide covers what JEE expects and how to test yourself with MCQs.

Concept explainer

Concept overview for Trigonometry covering 2 JEE syllabus subtopics including Trigonometrical identities and trigonometrical functions, Inverse trigonometrical functions and their properties.

Key points

  • Understand the definition and scope of Trigonometrical identities and trigonometrical functions in the JEE syllabus
  • Memorise key formulas and standard results linked to Trigonometrical identities and trigonometrical functions
  • Practise 20–40 syllabus-aligned MCQs with step-by-step solutions
  • Understand the definition and scope of Inverse trigonometrical functions and their properties in the JEE syllabus
  • Memorise key formulas and standard results linked to Inverse trigonometrical functions and their properties
  • Practise 20–40 syllabus-aligned MCQs with step-by-step solutions

JEE tips

  • Revise Trigonometrical identities and trigonometrical functions with a one-page formula sheet before attempting mixed tests
  • After each practice set, log mistakes specific to Trigonometrical identities and trigonometrical functions and reattempt after 48 hours
  • Revise Inverse trigonometrical functions and their properties with a one-page formula sheet before attempting mixed tests
  • After each practice set, log mistakes specific to Inverse trigonometrical functions and their properties and reattempt after 48 hours

Common trap

Students often rush Trigonometrical identities and trigonometrical functions questions without checking units, sign conventions, or boundary conditions — always verify assumptions before calculating.

JEE Formula Sheet

80+ important formulas for Trigonometry

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Subtopics in Trigonometry

View Trigonometry formula sheet — 80+ JEE formulas

Free sample questions

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Q1MathsUnit 14: Trigonometry
Assertion Consider f(x)=sin⁡−1(sec⁡(tan⁡−1x)+\boldsymbol{f}(\boldsymbol{x})=\sin ^{-1}\left(\sec \left(\tan ^{-1} \boldsymbol{x}\right)+\right. cos⁡−1(cosec⁡(cot⁡−1x)\cos ^{-1}\left(\operatorname{cosec}\left(\cot ^{-1} x\right)\right. Statement-1: Domain of f(x)f(x) is a singleton. Reason Statement-2: Range of the function f(x)\boldsymbol{f}(\boldsymbol{x}) is a singleton.
Q2MathsUnit 14: Trigonometry
The number of real solutions of the equation tan⁡−1x(x+1)+\tan ^{-1} \sqrt{x(x+1)}+ sin⁡−1x2+x+1=π2\sin ^{-1} \sqrt{x^{2}+x+1}=\frac{\pi}{2} is
Q3MathsUnit 14: Trigonometry
A=cos⁡200cos⁡400cos⁡600cos⁡800\mathbf{A}=\cos 20^{0} \cos 40^{0} \cos 60^{0} \cos 80^{0} B=cos⁡60cos⁡420cos⁡660cos⁡780\mathbf{B}=\cos 6^{0} \cos 42^{0} \cos 66^{0} \cos 78^{0} C=cos⁡360cos⁡720cos⁡1080cos⁡1440\mathbf{C}=\cos \mathbf{3} \mathbf{6}^{\mathbf{0}} \cos \mathbf{7} \mathbf{2}^{\mathbf{0}} \cos \mathbf{1 0} \mathbf{8}^{\mathbf{0}} \cos \mathbf{1} \mathbf{4} \mathbf{4}^{\mathbf{0}}
Q4MathsUnit 14: Trigonometry
The measures of the angles of a triangle are in the ratio 4:5:9.4: 5: 9 . The triangle is:
Q5MathsUnit 14: Trigonometry
If value of x\mathbf{x} which satisfy equation (cot⁡−1x)2−3(cot⁡−1x)+2>0\left(\cot ^{-1} x\right)^{2}-3\left(\cot ^{-1} x\right)+2>0 is x<x< cot⁡a\cot a or x>cot⁡bx>\cot b Find the value of a+ba+b
Q6MathsUnit 14: Trigonometry
ln⁡ΔABC,BC=AB\ln \Delta A B C, B C=A B and ∠B=80∘\angle B=80^{\circ} Then ∠A\angle A is equal to
Q7MathsUnit 14: Trigonometry
Two line segments ABA B and ACA C include an angle of 60060^{0} where AB=5cmA B=5 \mathrm{cm} and ACA C =7cm.=7 \mathrm{cm} . Locate points P\mathrm{P} and Q\mathrm{Q} on AB\mathrm{AB} and AC,A C, respectively such that AP=34A P=\frac{3}{4} ABA B and AQ=14AC.A Q=\frac{1}{4} A C . Join PP and QQ and measure the length PQ.
Q8MathsUnit 14: Trigonometry
Statement I: The equation (sin⁡−1x)3+(cos⁡−1x)3−aπ3=0\left(\sin ^{-1} x\right)^{3}+\left(\cos ^{-1} x\right)^{3}-a \pi^{3}=0 has solution for all a⩾132a \geqslant \frac{1}{32} Statement II : For any xϵR,sin−1x+\boldsymbol{x} \boldsymbol{\epsilon} \boldsymbol{R}, \boldsymbol{s} \boldsymbol{i n}^{-1} \boldsymbol{x}+ cos⁡−1x=π2\cos ^{-1} x=\frac{\pi}{2} and 0≤(sin⁡−1x−π4)2≤0 \leq\left(\sin ^{-1} x-\frac{\pi}{4}\right)^{2} \leq 9π216\frac{9 \pi^{2}}{16}

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What concepts in Trigonometry are essential for JEE?

Focus on core ideas across Trigonometrical identities and trigonometrical functions, Inverse trigonometrical functions and their properties. JEE tests application, not just memorisation.

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