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Medium Permutations and Combinations MCQs for JEE

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Medium Permutations and Combinations MCQs bridge basics and advanced JEE problems — 40+ available on Goodmarks.

Medium-difficulty Permutations and Combinations MCQs mirror typical JEE Main questions. Practise 40+ MCQs with step-by-step solutions.

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Q1MathsUnit 4: Permutations and Combinations
The total number of ways of formation of five letter words from the letters of the word INDEPENDENT,I N D E P E N D E N T, is
Q2MathsUnit 4: Permutations and Combinations
There are 4 balls of different colours &4\& 4 boxes of colours same as those of the balls. The number of ways in which the balls, one in each box, could be placed such that exactly no ball go to the box of its own colour is:
Q3MathsUnit 4: Permutations and Combinations
All the five digit numbers that can be formed using the digits 1,2,3,4,5 without repetition, are arranged in the decreasing order of magnitude. The rank of the number 34215 is
Q4MathsUnit 4: Permutations and Combinations
How many outcomes are possible when a coin is tossed
Q5MathsUnit 4: Permutations and Combinations
7 boys and 8 girls have to sit in a row on 15 chairs numbered from 1 to 15 then?
Q6MathsUnit 4: Permutations and Combinations
Find the correct co-related number. 5:36::6:?\mathbf{5}: \mathbf{3 6}:: \mathbf{6}: ?
Q7MathsUnit 4: Permutations and Combinations
Assertion In the shop there are five types of ice- creams available, a child buys six ice- creams. Reason The number of different ways the child can buy the six ice-creams is 10C3^{10} C_{3}
Q8MathsUnit 4: Permutations and Combinations
Arrange the following values of nn in ascending order. A:nP5=nP6⇒n=\boldsymbol{A}:^{n} \boldsymbol{P}_{5}=^{n} \boldsymbol{P}_{6} \Rightarrow \boldsymbol{n}= B:nP12=nP8⇒n=\boldsymbol{B}:^{\boldsymbol{n}} \boldsymbol{P}_{12}=^{\boldsymbol{n}} \boldsymbol{P}_{\boldsymbol{8}} \Rightarrow \boldsymbol{n}= C:nC(n−3)=10⇒n=\boldsymbol{C}:^{n} \boldsymbol{C}_{(\boldsymbol{n}-\mathbf{3})}=\mathbf{1 0} \Rightarrow \boldsymbol{n}= D:(n+1)P5:nP6=1:2⇒n=\boldsymbol{D}:^{(\boldsymbol{n}+1)} \boldsymbol{P}_{5}:^{\boldsymbol{n}} \boldsymbol{P}_{6}=\mathbf{1}: \boldsymbol{2} \Rightarrow \boldsymbol{n}=

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