General values at quadrantal angles for JEE

Formula

\(\sin n\pi=0,\quad \cos n\pi=(-1)^n,\quad \sin\left(\dfrac{(2n+1)\pi}{2}\right)=(-1)^n,\quad \cos\left(\dfrac{(2n+1)\pi}{2}\right)=0\)

Variables: \(n\in\mathbb{Z}\).

Evaluation of trig functions at standard multiples of \(\pi\).