Definite integral symmetry on [0,pi/2] for JEE

Formula

\[\int_0^{\pi/2} f(\sin x,\cos x)\,dx=\int_0^{\pi/2} f(\cos x,\sin x)\,dx\]

Variables: \(f\) is an expression in two arguments.

Conditions: Integrable on \([0,\pi/2]\).

Swapping sine and cosine in definite integrals.