Area of region bounded by parabola and its latus-rectum/chord forms via integration setup for JEE

Formula

\[\text{If } y^2=4ax,\ \text{then area between } x=\frac{y^2}{4a} \text{ and } x=h \text{ is } \int_{y_1}^{y_2}\left(h-\frac{y^2}{4a}\right)dy\]

Variables: \(a,h\) are constants; \(y_1,y_2\) are intersection ordinates.

Conditions: Choose limits from intersection points.

Standard parabola-bounded area questions.