Expansion of \((1+x)^n\) for JEE

Formula

\[(1+x)^n=1+nx+\frac{n(n-1)}{2!}x^2+\frac{n(n-1)(n-2)}{3!}x^3+\cdots+x^n\]

Variables: \(n\) is a positive integer.

Standard series-style expansion, approximation for small \(x\) when only first few terms are needed.